Problem 90 The surface area and average dep... [FREE SOLUTION] (2024)

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Chapter 1: Problem 90

The surface area and average depth of the Pacific Ocean are \(1.8 \times 10^{8}\mathrm{~km}^{2}\) and \(3.9 \times 10^{3} \mathrm{~m}\) respectively. Calculate the volume of water in the ocean in liters.

Short Answer

Expert verified

The volume of water in the Pacific Ocean is \(7.02 \times 10^{20}\) liters.

Step by step solution

01

- Convert Surface Area to Square Meters

The surface area of the Pacific Ocean is given as \(1.8 \times 10^8 \text{ km}^2\). Convert this to square meters by multiplying with \((10^3)^2\) (since \(1 \text{ km} = 10^3 \text{ m}\)). \[1.8 \times 10^8 \text{ km}^2 \times 10^6 = 1.8 \times 10^{14} \text{ m}^2\]

02

- Calculate the Volume in Cubic Meters

The average depth of the Pacific Ocean is given as \(3.9 \times 10^3 \text{ m}\). Multiply this depth by the surface area (in square meters) to obtain the volume in cubic meters. \[1.8 \times 10^{14} \text{ m}^2 \times 3.9 \times 10^3 \text{ m} = 7.02 \times 10^{17} \text{ m}^3\]

03

- Convert the Volume to Liters

Since 1 cubic meter equals 1000 liters, multiply the volume in cubic meters by 1000 to convert it into liters. \[7.02 \times 10^{17} \text{ m}^3 \times 10^3 = 7.02 \times 10^{20} \text{ liters}\]

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Area Conversion

To calculate the volume of the Pacific Ocean, we first need to convert the surface area from square kilometers to square meters. The given surface area is \(1.8 \times 10^8\) square kilometers. Here's why and how we convert it:

1. **Conversion Factor**: We know that 1 kilometer (km) equals 1000 meters (m).
2. **Conversion Process**: When converting square kilometers to square meters, we need to account for the squared units:

  • \(1 \text{ km}^2 = (10^3 \text{ m})^2\)
  • \(1 \text{ km}^2 = 10^6 \text{ m}^2\)

3. **Apply the Conversion**: Multiply the surface area in square kilometers by \(10^6\).
\[1.8 \times 10^8 \text{ km}^2 \times 10^6 = 1.8 \times 10^{14} \text{ m}^2\]
Now, we have the surface area in square meters which we will use in the volume calculation.

Volume Calculation

With the converted surface area, we next calculate the volume of the Pacific Ocean by considering its average depth. The given average depth is \(3.9 \times 10^3\) meters. For volume calculation, we use the formula:
\[\text{Volume} = \text{Surface Area} \times \text{Depth}\]
Here's how:

1. **Substitute Known Values**: The surface area is \(1.8 \times 10^{14} \text{ m}^2\) and the depth is \(3.9 \times 10^3 \text{ m}\).
2. **Calculate**:
\[1.8 \times 10^{14} \text{ m}^2 \times 3.9 \times 10^3 \text{ m} = 7.02 \times 10^{17} \text{ m}^3\]
Thus, the volume of the Pacific Ocean in cubic meters is \(7.02 \times 10^{17} \text{ m}^3\). This step gives us the volume in cubic meters, which is essential for the final conversion.

Unit Conversion

Finally, to determine the volume of the Pacific Ocean in liters, we convert the volume from cubic meters to liters. The conversion factor here is straightforward, as 1 cubic meter equals 1000 liters.

1. **Volume in Cubic Meters**: We have \(7.02 \times 10^{17} \text{ m}^3\).
2. **Conversion Factor**: 1 cubic meter equals 1000 liters.
3. **Apply the Conversion**:
\[7.02 \times 10^{17} \text{ m}^3 \times 10^3 = 7.02 \times 10^{20} \text{ liters}\]
Therefore, the volume of the Pacific Ocean is \(7.02 \times 10^{20} \text{ liters}\). By understanding and applying these unit conversions properly, we can find the volume in whatever unit is required for interpretation.

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Problem 90 The surface area and average dep... [FREE SOLUTION] (31)

Most popular questions from this chapter

Give one qualitative and one quantitative statement about each of thefollowing: (a) water, (b) carbon, (c) iron, (d) hydrogen gas, (e) sucrose(cane sugar), (f) table salt, (g) mercury, (h) gold, (i) air.Classify each of the following as a pure substance, a hom*ogeneous mixture, ora heterogeneous mixture: (a) seawater, (b) helium gas, (c) salt, (d) dietcola, (e) a milkshake, (f) bottled water, (g) concrete, (h) \(24 \mathrm{~K}\)gold, (i) liquid nitrogen.Write the numbers represented by the following prefixes: (a) mega-, (b) kilo-,(c) deci-, (d) centi-, (e) milli-, (f) micro-, (g) nano-, (h) pico-.(a) Normally the human body can endure a temperature of \(105^{\circ}\mathrm{F}\) for only short periods of time without permanent damage to thebrain and other vital organs. What is this temperature in degrees Celsius? (b)Ethylene glycol is a liquid that is used as an antifreeze in car radiators. Itfreezes at \(-11.5^{\circ} \mathrm{C} .\) Calculate its freezing temperature indegrees Fahrenheit. (c) The temperature on the surface of the sun is about\(6300^{\circ} \mathrm{C}\). What is this temperature in degrees Fahrenheit?Carry out the following operations as if they were calculations ofexperimental results, and express each answer in the correct units with thecorrect number of significant figures: (a) \(7.310 \mathrm{~km} \div 5.70 \mathrm{~km}\), (b) \(\left(3.26 \times 10^{-3} \mathrm{mg}\right)-\left(7.88 \times 10^{-5}\mathrm{mg}\right)\) (c) \(\left(4.02 \times 10^{6} \mathrm{dm}\right)+\left(7.74 \times 10^{7}\mathrm{dm}\right)\)
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Problem 90 The surface area and average dep... [FREE SOLUTION] (2024)
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